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Fixed incorrectly translated choice rules with multiple elements in the aggregate.

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This commit is contained in:
Patrick Lühne 2017-03-23 02:06:19 +01:00
parent 283cdd2abf
commit 09c2674148
Signed by: patrick
GPG Key ID: 05F3611E97A70ABF
3 changed files with 62 additions and 28 deletions
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61
include/anthem/StatementVisitor.h
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@ -47,7 +47,7 @@ struct StatementVisitor
return {};
}
// Print auxiliary variables replacing the head atom’s arguments
// Generate auxiliary variables replacing the head atom’s arguments
for (auto i = context.headTerms.cbegin(); i != context.headTerms.cend(); i++)
{
const auto &headTerm = **i;
@ -60,7 +60,7 @@ struct StatementVisitor
antecedent.arguments.emplace_back(std::move(in));
}
// Print translated body literals
// Translate body literals
for (auto i = rule.body.cbegin(); i != rule.body.cend(); i++)
{
const auto &bodyLiteral = *i;
@ -76,17 +76,56 @@ struct StatementVisitor
antecedent.arguments.emplace_back(std::move(argument.value()));
}
// Handle choice rules
if (context.isChoiceRule)
antecedent.arguments.emplace_back(ast::deepCopy(consequent.value()));
std::vector<ast::Formula> formulas;
// Use “true” as the consequent in case it is empty
if (antecedent.arguments.empty())
return {ast::Formula::make<ast::Implies>(ast::Boolean(true), std::move(consequent.value()))};
else if (antecedent.arguments.size() == 1)
return {ast::Formula::make<ast::Implies>(std::move(antecedent.arguments[0]), std::move(consequent.value()))};
if (!context.isChoiceRule)
formulas.emplace_back(ast::Formula::make<ast::Implies>(std::move(antecedent), std::move(consequent.value())));
else
{
const auto createFormula =
[&](ast::Formula &argument, bool isLastOne)
{
auto consequent = std::move(argument);
return {ast::Formula::make<ast::Implies>(std::move(antecedent), std::move(consequent.value()))};
if (!isLastOne)
formulas.emplace_back(ast::Formula::make<ast::Implies>(ast::deepCopy(antecedent), std::move(consequent)));
else
formulas.emplace_back(ast::Formula::make<ast::Implies>(std::move(antecedent), std::move(consequent)));
auto &implies = formulas.back().get<ast::Implies>();
auto &antecedent = implies.antecedent.get<ast::And>();
antecedent.arguments.emplace_back(ast::deepCopy(implies.consequent));
};
if (consequent.value().is<ast::Or>())
{
auto &disjunction = consequent.value().get<ast::Or>();
for (auto &argument : disjunction.arguments)
createFormula(argument, &argument == &disjunction.arguments.back());
}
// TODO: check whether this is really correct for all possible consequent types
else
createFormula(consequent.value(), true);
}
for (auto &formula : formulas)
{
auto &implies = formula.get<ast::Implies>();
auto &antecedent = implies.antecedent.get<ast::And>();
// Use “true” as the consequent in case it is empty
if (antecedent.arguments.empty())
implies.antecedent = ast::Formula::make<ast::Boolean>(true);
else if (antecedent.arguments.size() == 1)
{
// TODO: remove workaround
auto tmp = std::move(antecedent.arguments[0]);
implies.antecedent = std::move(tmp);
}
}
return formulas;
}
std::vector<ast::Formula> visit(const Clingo::AST::Definition &, const Clingo::AST::Statement &statement, Context &context)

21
src/anthem/Translation.cpp
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@ -41,29 +41,24 @@ void translate(const char *fileName, std::istream &stream, Context &context)
bool isFirstStatement = true;
const auto printFormula =
[&context, &isFirstStatement](const ast::Formula &formula)
{
if (!isFirstStatement)
context.logger.outputStream() << std::endl;
context.logger.outputStream() << formula << std::endl;
isFirstStatement = false;
};
const auto translateStatement =
[&context, &printFormula](const Clingo::AST::Statement &statement)
[&context, &isFirstStatement](const Clingo::AST::Statement &statement)
{
auto formulas = statement.data.accept(StatementVisitor(), statement, context);
if (!isFirstStatement)
context.logger.outputStream() << std::endl;
for (auto &formula : formulas)
{
if (context.simplify)
simplify(formula);
printFormula(formula);
context.logger.outputStream() << formula << std::endl;
}
if (!formulas.empty())
isFirstStatement = false;
};
const auto logger =

8
tests/TestTranslation.cpp
View File

@ -226,7 +226,7 @@ TEST_CASE("[translation] Rules are translated correctly", "[translation]")
input << "{p; q}.";
anthem::translate("input", input, context);
REQUIRE(output.str() == "((p or q) -> (p or q))\n");
REQUIRE(output.str() == "(p -> p)\n(q -> q)\n");
}
SECTION("choice rule (n-ary elements)")
@ -234,7 +234,7 @@ TEST_CASE("[translation] Rules are translated correctly", "[translation]")
input << "{p(1..3, N); q(2..4)}.";
anthem::translate("input", input, context);
REQUIRE(output.str() == "((V1 in 1..3 and V2 in N and V3 in 2..4 and (p(V1, V2) or q(V3))) -> (p(V1, V2) or q(V3)))\n");
REQUIRE(output.str() == "((V1 in 1..3 and V2 in N and V3 in 2..4 and p(V1, V2)) -> p(V1, V2))\n((V1 in 1..3 and V2 in N and V3 in 2..4 and q(V3)) -> q(V3))\n");
}
SECTION("choice rule with body")
@ -242,7 +242,7 @@ TEST_CASE("[translation] Rules are translated correctly", "[translation]")
input << "{p(M, N); q(P)} :- s(M, N, P).";
anthem::translate("input", input, context);
REQUIRE(output.str() == "((V1 in M and V2 in N and V3 in P and exists X1, X2, X3 (X1 in M and X2 in N and X3 in P and s(X1, X2, X3)) and (p(V1, V2) or q(V3))) -> (p(V1, V2) or q(V3)))\n");
REQUIRE(output.str() == "((V1 in M and V2 in N and V3 in P and exists X1, X2, X3 (X1 in M and X2 in N and X3 in P and s(X1, X2, X3)) and p(V1, V2)) -> p(V1, V2))\n((V1 in M and V2 in N and V3 in P and exists X1, X2, X3 (X1 in M and X2 in N and X3 in P and s(X1, X2, X3)) and q(V3)) -> q(V3))\n");
}
SECTION("choice rule with negation")
@ -258,6 +258,6 @@ TEST_CASE("[translation] Rules are translated correctly", "[translation]")
input << "{not p(X, 1); not s} :- not q(X, 2).";
anthem::translate("input", input, context);
REQUIRE(output.str() == "((V1 in X and V2 in 1 and exists X1, X2 (X1 in X and X2 in 2 and not q(X1, X2)) and (not p(V1, V2) or not s)) -> (not p(V1, V2) or not s))\n");
REQUIRE(output.str() == "((V1 in X and V2 in 1 and exists X1, X2 (X1 in X and X2 in 2 and not q(X1, X2)) and not p(V1, V2)) -> not p(V1, V2))\n((V1 in X and V2 in 1 and exists X1, X2 (X1 in X and X2 in 2 and not q(X1, X2)) and not s) -> not s)\n");
}
}