Add new simplification rule

This adds the rule “not not F === F” to the simplification rule tableau.

src/anthem/Simplification.cpp

@@ -379,9 +379,34 @@ struct SimplificationRuleSubsumptionInBiconditionals
 
 ////////////////////////////////////////////////////////////////////////////////////////////////////
 
+struct SimplificationRuleDoubleNegation
+{
+	static constexpr const auto Description = "not not F === F";
+
+	static SimplificationResult apply(ast::Formula &formula)
+	{
+		if (!formula.is<ast::Not>())
+			return SimplificationResult::Unchanged;
+
+		auto &not_ = formula.get<ast::Not>();
+
+		if (!not_.argument.is<ast::Not>())
+			return SimplificationResult::Unchanged;
+
+		auto &notNot = not_.argument.get<ast::Not>();
+
+		formula = std::move(notNot.argument);
+
+		return SimplificationResult::Simplified;
+	}
+};
+
+////////////////////////////////////////////////////////////////////////////////////////////////////
+
 const auto simplifyWithDefaultRules =
 	simplify
 	<
+		SimplificationRuleDoubleNegation,
 		SimplificationRuleTrivialAssignmentInExists,
 		SimplificationRuleAssignmentInExists,
 		SimplificationRuleEmptyConjunction,

tests/TestHiddenPredicateElimination.cpp

@@ -103,9 +103,10 @@ TEST_CASE("[hidden predicate elimination] Hidden predicates are correctly elimin
 			"#show a/1.";
 		anthem::translate("input", input, context);
 
+		// TODO: simplify further
 		CHECK(output.str() ==
 			"forall V1 (a(V1) <-> not d(V1))\n"
-			"forall V2 (d(V2) <-> not not d(V2))\n"
+			"forall V2 (d(V2) <-> d(V2))\n"
 			"forall V3 (e(V3) <-> e(V3))\n");
 	}