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Code Issues 15 Releases 21 Activity

Move simplification rule to tableau

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This moves the rule “[primitive A] in [primitive B] === A = B” to the
simplification rule tableau.
This commit is contained in:
Patrick Lühne 2018-03-25 20:35:22 +02:00
parent 107dae7287
commit c4c3156e77
Signed by: patrick
GPG Key ID: 05F3611E97A70ABF
1 changed files with 26 additions and 7 deletions
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33
src/anthem/Simplification.cpp
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@ -317,6 +317,30 @@ struct SimplificationRuleTrivialExists
////////////////////////////////////////////////////////////////////////////////////////////////////
struct SimplificationRuleInWithPrimitiveArguments
{
static constexpr const auto Description = "[primitive A] in [primitive B] === A = B";
static SimplificationResult apply(ast::Formula &formula)
{
if (!formula.is<ast::In>())
return SimplificationResult::Unchanged;
auto &in = formula.get<ast::In>();
assert(ast::isPrimitive(in.element));
if (!ast::isPrimitive(in.element) || !ast::isPrimitive(in.set))
return SimplificationResult::Unchanged;
formula = ast::Comparison(ast::Comparison::Operator::Equal, std::move(in.element), std::move(in.set));
return SimplificationResult::Simplified;
}
};
////////////////////////////////////////////////////////////////////////////////////////////////////
void simplify(ast::Exists &exists, ast::Formula &formula)
{
SimplificationRuleTrivialAssignmentInExists::apply(formula);
@ -341,14 +365,9 @@ struct SimplifyFormulaVisitor : public ast::RecursiveFormulaVisitor<SimplifyForm
}
// Simplify formulas of type “A in B” to “A = B” if A and B are primitive
static void accept(ast::In &in, ast::Formula &formula)
static void accept(ast::In &, ast::Formula &formula)
{
assert(ast::isPrimitive(in.element));
if (!ast::isPrimitive(in.element) || !ast::isPrimitive(in.set))
return;
formula = ast::Comparison(ast::Comparison::Operator::Equal, std::move(in.element), std::move(in.set));
SimplificationRuleInWithPrimitiveArguments::apply(formula);
}
// Do nothing for all other types of expressions