Added example for attempting to hide a circular predicate dependency.
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								examples/hide-circular-dependency.lp
									
									
									
									
									
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								examples/hide-circular-dependency.lp
									
									
									
									
									
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a(X) :- circle1(X).
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circle1(X) :- circle2(X).
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circle2(X) :- circle3(X).
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circle3(X) :- circle1(X).
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#show a/1.
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%#show circle1/1.
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%#show circle2/1.
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%#show circle3/1.
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